W W
L
2W + L = 40
L= 40–2w
A (W)= W(20–2W) –2W2 +40W =0
-b = —40 = 40 = 10
2a –2(2) 10
A (10) 10(40-2(10) ) = 10( 20 ) = 200m
Toni Wilson Posted new comment
Maximize the Area
paint your math problem
paint your math problem
W W
L
2W + L = 40
L= 40–2w
A (W)= W(20–2W) –2W2 +40W =0
-b = —40 = 40 = 10
2a –2(2) 10
A (10) 10(40-2(10) ) = 10( 20 ) = 200m
I meant 200m^2